5(3-4x)^2-8(3-4x)(5x-1)=0

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Solution for 5(3-4x)^2-8(3-4x)(5x-1)=0 equation: 



5(3-4x)^2-8(3-4x)(5x-1)=0

We add all the numbers together, and all the variables

5(-4x+3)^2-8(-4x+3)(5x-1)=0

We multiply parentheses ..

-8(-20x^2+4x+15x-3)+5(-4x+3)^2=0

We multiply parentheses

160x^2-32x-120x+5(-4x+3)^2+24=0

We add all the numbers together, and all the variables

160x^2-152x+5(-4x+3)^2+24=0

We move all terms containing x to the left, all other terms to the right

160x^2-152x+5(-4x+3)^2=-24

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